Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.6 Rational Expressions - A.6 Assess Your Understanding - Page A53: 37



Work Step by Step

Since the denominators are the same, we have $$ \frac{x^2}{2x-3}-\frac{4}{2x-3}=\frac{x^2-4}{2x-3}=\frac{(x-2)(x+2)}{2x-3} $$
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