Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.6 Rational Expressions - A.6 Assess Your Understanding - Page A53: 5



Work Step by Step

By factoring both the denominator and numerator and canceling out the common factors, we have $$ \frac{3x+9}{x^2-9}=\frac{3(x+3)}{(x-3)(x+3)}=\frac{3}{x-3} .$$
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