Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.6 Rational Expressions - A.6 Assess Your Understanding - Page A53: 6

Answer

$\dfrac{x}{3}$

Work Step by Step

By factoring both the denominator and the numerator and then cancelling the common factors, we have $$ \frac{4x^2+8x}{12x+24}=\frac{4x(x+2)}{12(x+2)}=\frac{x}{3} $$
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