Answer
$\dfrac{3x}{4(3x+5)}$
Work Step by Step
By factoring both the denominator and numerator of each rational function and cancelling the common factors, we have
$$
\frac{3}{2x}\cdot \frac{x^2}{6x+10} =\frac{3}{2x}\cdot \frac{x^2}{2(3x+5)} \\
= \frac{3x}{4(3x+5)}
.$$
