Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.6 Rational Expressions - A.6 Assess Your Understanding - Page A53: 20



Work Step by Step

By factoring both the denominator and numerator of each rational function and cancelling the common factors, we have $$ \frac{12}{x^2+x}\cdot \frac{x^3+1}{4x-2} = \frac{12}{x(x+1)}\cdot \frac{(x+1)(x^2-x+1)}{2(2x-1)}\\ = \frac{6(x^2-x+1)}{x(2x-1)} .$$
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