Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.11 Complex Numbers - A.11 Assess Your Understanding - Page A94: 8

Answer

$\text{True }$

Work Step by Step

Note that: \begin{align*} (a+ib)(a-bi)&=a^2-b^2i^2&\\ &=a^2-b^2(-1)\\ &=a^2+b^2\end{align*} Since both $a^2$ and $b^2$ are non-negative, then the given statement is true.
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