Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.11 Complex Numbers - A.11 Assess Your Understanding - Page A94: 18

Answer

$-12-9i$

Work Step by Step

Distribute $3i$ to remove the parentheses and use the fact that $i^2=-1$, to obtain: $$ 3i(-3+4i)=3i(-3)+3i(4i) \\=-9i+12i^2 \\=-9i+12(-1) \\=-12-9i $$
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