Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.11 Complex Numbers - A.11 Assess Your Understanding - Page A94: 34



Work Step by Step

Using the facts that $i=\sqrt{-1}$, $i^2=-1$, $i^3=-i$, $i^4=1$, and $a^{b+c}=a^b\cdot a^c$, we have: $$ i^{14}=i^{2+12}=i^2\cdot i^{12}=i^2(i^4)^3=i^2=-1 $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.