# Appendix A - Review - A.11 Complex Numbers - A.11 Assess Your Understanding - Page A94: 34

$-1$

#### Work Step by Step

Using the facts that $i=\sqrt{-1}$, $i^2=-1$, $i^3=-i$, $i^4=1$, and $a^{b+c}=a^b\cdot a^c$, we have: $$i^{14}=i^{2+12}=i^2\cdot i^{12}=i^2(i^4)^3=i^2=-1$$

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