Answer
$13+i$
Work Step by Step
Multiply each term of the first complex number by each term of the second, then combine like terms and use the fact that $i^2=-1$ to obtain:
$$
(5+3i)(2-i)=5(2-i)+3i(2-i)
\\=10-5i+6i-3i^2
\\=10+i-3(-1)
\\=10+i+3
\\=13+i
$$
