Answer
$6+4i$
Work Step by Step
Distribute $2i$ to remove the parentheses and use the fact that $i^2=-1$ to obtain:
\begin{align*}2i(2 - 3i)&= 2i(2)-2i(3i)\\
&=4i-6i^2\\
&=4i-6(-1)\\
&=4i+6\\
&=6+4i
\end{align*}
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.11 Complex Numbers - A.11 Assess Your Understanding - Page A94: 17
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