Answer
$-\frac{1}{2}+\frac{\sqrt 3}{2}i$
Work Step by Step
$(\frac{1}{2}+\frac{\sqrt 3}{2}i)^2=(\frac{1}{2})^2+2(\frac{1}{2})(\frac{\sqrt 3}{2}i)+(\frac{\sqrt 3}{2}i)^2=\frac{1}{4}+\frac{\sqrt 3}{2}i-\frac{3}{4}=-\frac{1}{2}+\frac{\sqrt 3}{2}i$
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