Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.11 Complex Numbers - A.11 Assess Your Understanding - Page A94: 5

Answer

$-1, \quad-i, \quad 1$

Work Step by Step

Since $i=\sqrt{-1}$, then we have $$ i^2=(\sqrt{-1})^2=-1\\ i^3=(\sqrt{-1})^3=-1\sqrt{-1}=-i\\ i^4=(\sqrt{-1})^4=1 $$
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