## Precalculus (6th Edition)

$\color{blue}{11\sqrt{2k}}$
Simplify each radical. Factor the radicand so that one factor is a perfect square, then bring out the square root of the perfect square factor to obtain: $=4\sqrt{9(2k)}-\sqrt{36(2k)} +\sqrt{25(2k)} \\=4\cdot 3\sqrt{2k}-6\sqrt{2k}+5\sqrt{2k} \\=12\sqrt{2k}-6\sqrt{2k}+5\sqrt{2k}$ Combine like terms to obtain: $=(12-6+5)\sqrt{2k} \\=\color{blue}{11\sqrt{2k}}$