## Precalculus (6th Edition)

$\color{blue}{5k^2|m|}$
RECALL: If $n$ is an even integer, $\sqrt[n]{a^n} = |a|$ Using the rule above gives: $\sqrt{25k^4m^2} \\=\sqrt{5^2k^4m^2} \\= {|5k^2m|} \\=\color{blue}{5k^2|m|}$