## Precalculus (6th Edition)

$\color{blue}{\dfrac{gh^2\sqrt{ghr}}{r^2}}$
Rationalize the denominator by multiplying $r$ to both the numerator and denominator of the radicand to obtain: $=\sqrt{\dfrac{g^3h^5(r)}{r^3(r)}} \\=\sqrt{\dfrac{g^3h^5(r)}{r^4}} \\=\sqrt{\dfrac{g^3h^5(r)}{(r^2)^2}}$ Bring out the square root of the denominator to obtain: $\\=\dfrac{\sqrt{g^3h^5r}}{r^2}$ Factor the radicand such that at least one factor is a perfect square to obtain: $\\=\dfrac{\sqrt{(g^2h^4)(ghr)}}{r^2} \\=\dfrac{\sqrt{(gh^2)^2(ghr)}}{r^2}$ Bring out the square root of the perfect square factor/s of the numerator to obtain: $\\=\color{blue}{\dfrac{gh^2\sqrt{ghr}}{r^2}}$