# Chapter R - Review of Basic Concepts - R.7 Radical Expressions - R.7 Exercises - Page 75: 63

$\color{blue}{\dfrac{\sqrt{6x}}{3x}}$

#### Work Step by Step

Rationalize the denominator by multiplying $3x$ to both the numerator and the denominator of the radicand to obtain: $=\sqrt{\dfrac{2(3x)}{(3x)(3x)}} \\=\sqrt{\dfrac{6x}{(3x)^2}}$ Bring out the square root of the denominator to obtain: $=\color{blue}{\dfrac{\sqrt{6x}}{3x}}$

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