## Precalculus (6th Edition)

$\color{blue}{-\frac{1}{2}\sqrt[4]{3}}$
Factor the radicand so that one factor is a perfect fourth power to obtain: $=-\sqrt[4]{\left(\frac{1}{16}\right)(3)} \\=-\sqrt{\left(\frac{1}{2}\right)^4(3)}$ Bring out the cube root of the perfect cube factor to obtain: $\\=\color{blue}{-\frac{1}{2}\sqrt[4]{3}}$