Precalculus (6th Edition)

$\color{blue}{2m^3n^2\sqrt{6n}}$
Factor the radicand so that at least one factor is a perfect square to obtain: $=\sqrt{4(6)(m^6)(n^4)(n)} \\=\sqrt{(4m^6n^4)(6n)} \\=\sqrt{2^2(m^3)^2(n^2)^2(6n)}$ Bring out the square root of the perfect square factors to obtain: $=2\cdot m^3\cdot n^2\sqrt{6n} \\=\color{blue}{2m^3n^2\sqrt{6n}}$