## Precalculus (6th Edition)

$\color{blue}{\dfrac{x^2y\sqrt{xy}}{z}}$
Bring out the square root of the denominator to obtain: $=\dfrac{1}{z} \cdot \sqrt{x^5y^3} \\=\dfrac{\sqrt{x^5y^3}}{z}$ Factor the radicand such that at least one factor is a perfect square to obtain: $\\=\dfrac{\sqrt{(x^4y^2)(xy)}}{z} \\=\dfrac{\sqrt{(x^2y)^2(xy)}}{z}$ Bring out the square root of the perfect square factor/s of the numerator to obtain: $\\=\color{blue}{\dfrac{x^2y\sqrt{xy}}{z}}$