Precalculus (6th Edition)

The given statement is false. A corrected statement is: $(x+y)^2 = x^2 + 2xy + y^2$
RECALL: $(a+b)^2=a^2+2ab + b^2$ Use the rule above with $a=x$ and $b=y$ to obtain: $=x^2 + 2(x)(y) + y^2 \\=x^2xy+y^2$ Thus, the given statement is false. A corrected statement is: $(x+y)^2 = x^2 + 2xy + y^2$