Answer
$ \frac{256n^8}{t^4p^8}$.
Work Step by Step
The rule $(\frac{a}{b})^n = \frac{a^n}{b^n}$.
$(\frac{-4n^2}{tp^2})^4 = \frac{(-4)^4n^{2\times4}}{t^4p^{2\times4}} = \frac{256n^8}{t^4p^8}$.
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises - Page 32: 31
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