## Precalculus (6th Edition)

Published by Pearson

# Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises - Page 32: 7

true

#### Work Step by Step

RECALL: $a^m \cdot a^n = a^{m+n}$ Thus, $y^2 \cdot y^5 = y^{2+5} = y^7$ Therefore, the given statement is true.

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