Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises: 22

Answer

$-10m^5n^3$

Work Step by Step

RECALL: $a^m \cdot a^n = a^{m+n}$ Use the rule above to obtain: $=[35 \cdot (-\frac{2}{7})]m^{4+1}n^{1+2} \\=[35 \cdot (-\frac{2}{7})]m^5n^3$ Cancel the common factor $7$ to obtain: $\require{cancel}\\=[\cancel{35}^5 \cdot (-\frac{2}{\cancel{7}})]m^5n^3 \\=-10m^5n^3$
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