Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises - Page 32: 28


$ -8y^{12}$

Work Step by Step

$-(2x^0y^4)^3$ $= -(2^3x^{0\times3}y^{4\times3})$ $ = -(8x^0y^{12})$ $ = -8y^{12}$
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