Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises: 32

Answer

$\frac{-125n^{12}}{r^2}$

Work Step by Step

The rules $(\frac{a}{b})^n = \frac{a^n}{b^n}$, $(a^m)^n = a^{mn}$. $\frac{(-5n^4)^3}{r^2} = \frac{(-5)^3 n^{4\times3}}{r^2} = \frac{-125n^{12}}{r^2}$
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