Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises - Page 32: 21

Answer

$4m^3n^3$

Work Step by Step

RECALL: $a^m \cdot a^n = a^{m+n}$ Use the rule above to obtain: $=(\frac{1}{2} \cdot 8)m^{1+2}n^{1+2} \\=4m^3n^3$
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