Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 9 - Systems and Matrices - 9.3 Determinant Solution of Linear Systems - 9.3 Exercises - Page 887: 99

Answer

$$\left\{ { - 4} \right\}$$

Work Step by Step

$$\eqalign{ & \left| {\matrix{ { - 2} & 0 & 1 \cr { - 1} & 3 & x \cr 5 & { - 2} & 0 \cr } } \right| = 3 \cr & {\rm{Expand \,the \,determinant\, to\, obtain}} \cr & - 2\left| {\matrix{ 3 & x \cr { - 2} & 0 \cr } } \right| - 0 + 1\left| {\matrix{ { - 1} & 3 \cr 5 & { - 2} \cr } } \right| = 3 \cr & - 2\left( {0 + 2x} \right) + \left( {2 - 15} \right) = 3 \cr & {\rm{Solve\, the\, equation}} \cr & - 4x - 13 = 3 \cr & - 4x = 16 \cr & x = - 4 \cr & {\rm{The\, solution\, set \,is}} \cr & \left\{ { - 4} \right\} \cr} $$
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