Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 9 - Systems and Matrices - 9.3 Determinant Solution of Linear Systems - 9.3 Exercises - Page 887: 100

Answer

$$\left\{ { - 2} \right\}$$

Work Step by Step

$$\eqalign{ & \left| {\matrix{ 4 & 3 & 0 \cr 2 & 0 & 1 \cr { - 3} & x & { - 1} \cr } } \right| = 5 \cr & {\rm{Expand \,the\, determinant \,to\, obtain}} \cr & - 2\left| {\matrix{ 3 & 0 \cr x & { - 1} \cr } } \right| + 0 - 1\left| {\matrix{ 4 & 3 \cr { - 3} & x \cr } } \right| = 5 \cr & - 2\left( { - 3 + 0} \right) - \left( {4x + 9} \right) = 5 \cr & {\rm{Solve\, the\, equation}} \cr & 6 - 4x - 9 = 5 \cr & - 4x = 8 \cr & x = - 2 \cr & {\rm{The\, solution\, set\, is}} \cr & \left\{ { - 2} \right\} \cr} $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.