Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.3 Logarithmic Functions - 4.3 Exercises - Page 446: 88

Answer

$log_a(\frac{1}{p^2})$

Work Step by Step

$\frac{1}{2}log_a(p^3q^4)-\frac{2}{3}log_a(p^4q^3)=log_a(p^{3/2}q^2)-log_a(p^{8/3}q^2)=log_a(\frac{p^{3/2}q^2}{p^{8/3}q^2})=log_a(\frac{1}{p^2})$
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