Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.3 Logarithmic Functions - 4.3 Exercises - Page 446: 82

Answer

$\dfrac {1}{3}\log _{4}a+\dfrac {1}{4}\log _{4}b-\dfrac {1}{2}\log _{4}c-\dfrac {2}{3}\log _{4}d$

Work Step by Step

$\log _{4}\dfrac {\sqrt [3] {a}\times \sqrt [4] {b}}{\sqrt {c}\sqrt [3] {d^{2}}}=\log _{4}\left( a^{\dfrac {1}{3}}b^{\dfrac {1}{4}}c^{-\dfrac {1}{2}}d^{-\dfrac {2}{3}}\right) =\dfrac {1}{3}\log _{4}a+\dfrac {1}{4}\log _{4}b-\dfrac {1}{2}\log _{4}c-\dfrac {2}{3}\log _{4}d$
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