Answer
$2\log _{3}2+\log _{3}p-\log _{3}q$
Work Step by Step
$\log _{3}\dfrac {4p}{q}=\log _{34}p-\log _{3}q=\log _{3}4+\log _{3}p-\log _{3}q=\log _{3}2^{2}+\log _{3}p-\log _{3}q=2\log _{3}2+\log _{3}p-\log _{3}q$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.3 Logarithmic Functions - 4.3 Exercises - Page 446: 72
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