Answer
$1+\dfrac {1}{2}\log _{5}7-\log _{5}3$
Work Step by Step
$\log _{5}\dfrac {5\sqrt {7}}{3}=\log _{5}5+\log _{5}\sqrt {7}-\log _{5}3=1+\log _{5}7^{1/2}-\log _{5}3=1+\dfrac {1}{2}\log _{5}7-\log _{5}3$
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