Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.3 Logarithmic Functions - 4.3 Exercises - Page 446: 71

Answer

$\log _{2}6+\log _{2}x-\log _{2}y$

Work Step by Step

$\log _{2}\dfrac {6x}{y}=\log _{2}6x-\log _{2}y=\log _{2}6+\log _{2}x-\log _{2}y$
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