#### Answer

$1+\dfrac {1}{2}\log _{2}3-\log _{2}5$

#### Work Step by Step

$$\log _{2}\dfrac {2\sqrt {3}}{5}=\log _{2}2^{1}\times 3^{\dfrac {1}{2}}\times 5^{-1}=\log _{2}2+\log _{2}3^{1/2}-\log _{2}5=1+\dfrac {1}{2}\log _{2}3-\log _{2}5$$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$1+\dfrac {1}{2}\log _{2}3-\log _{2}5$

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