#### Answer

$\log _b \dfrac {p}{qr}$

#### Work Step by Step

$\log _{b}p-\log _{b}q-\log _{b}r=\left( \log _{b}p-\log _{b}q\right) -\log _{b}r=\log_b \dfrac {p}{q}-\log _{b}r=\log _b \dfrac {p}{qr}$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$\log _b \dfrac {p}{qr}$

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