Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises - Page 1015: 85


$\sum ^{9}_{i=1}\dfrac {1}{3i}$

Work Step by Step

$\dfrac {1}{3\left( 1\right) }+\dfrac {1}{3\left( 2\right) }+\dfrac {1}{3\left( 3\right) }...=\dfrac {1}{3\times 1}+\dfrac {1}{3\times 2}+\dfrac {1}{3\times 3}+\ldots +\dfrac {1}{3\times 9}=\sum ^{9}_{i=1}\dfrac {1}{3i}$
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