Answer
$-1+1+3+5+7$, $15$
Work Step by Step
$\sum_{i=1}^5(2x_i+3)$
$=(2x_1+3)+(2x_2+3)+(2x_3+3)+(2x_4+3)+(2x_5+3)$
$=(2*(-2)+3)+(2*(-1)+3)+(2*0+3)+(2*1+3)+(2*2+3)$
$=-1+1+3+5+7$
$=\boxed{15}$
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