Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises - Page 1015: 61


$-1+1+3+5+7$, $15$

Work Step by Step

$\sum_{i=1}^5(2x_i+3)$ $=(2x_1+3)+(2x_2+3)+(2x_3+3)+(2x_4+3)+(2x_5+3)$ $=(2*(-2)+3)+(2*(-1)+3)+(2*0+3)+(2*1+3)+(2*2+3)$ $=-1+1+3+5+7$ $=\boxed{15}$
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