#### Answer

$-1+1+3+5+7$, $15$

#### Work Step by Step

$\sum_{i=1}^5(2x_i+3)$
$=(2x_1+3)+(2x_2+3)+(2x_3+3)+(2x_4+3)+(2x_5+3)$
$=(2*(-2)+3)+(2*(-1)+3)+(2*0+3)+(2*1+3)+(2*2+3)$
$=-1+1+3+5+7$
$=\boxed{15}$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$-1+1+3+5+7$, $15$

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