Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises: 62

Answer

$4+1+(-2)+(-5)$ $-2$

Work Step by Step

$\sum_{i=1}^4(-3x_i-2)$ $=(-3x_1-2)+(-3x_2-2)+(-3x_3-2)+(-3x_4-2)$ $=(-3*(-2)-2)+(-3*(-1)-2)+(-3*0-2)+(-3*1-2)$ $=4+1+(-2)+(-5)$ $=\boxed{-2}$
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