Precalculus (6th Edition)

Published by Pearson

Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises - Page 1015: 66

Answer

$-2+(-\frac{1}{2})+0+\frac{1}{4}+\frac{2}{5}$ $=-\frac{37}{20}$

Work Step by Step

$\sum_{i=1}^5\frac{x_i}{x_i+3}$ $=\frac{x_1}{x_1+3}+\frac{x_2}{x_2+3}+\frac{x_3}{x_3+3}+\frac{x_4}{x_4+3}+\frac{x_5}{x_5+3}$ $=\frac{-2}{-2+3}+\frac{-1}{-1+3}+\frac{0}{0+3}+\frac{1}{1+3}+\frac{2}{2+3}$ $=-2+(-\frac{1}{2})+0+\frac{1}{4}+\frac{2}{5}$ $=\boxed{-\frac{37}{20}}$

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