Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises - Page 1015: 64


$2+0+0$ $=2$

Work Step by Step

$\sum_{i=1}^3({x_i}^2+x_i)$ $=({x_1}^2+x_1)+({x_2}^2+x_2)+({x_3}^2+x_3)$ $=((-2)^2+(-2))+((-1)^2+(-1))+(0^2+0)$ $=2+0+0$ $=\boxed{2}$
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