Answer
$2+0+0$
$=2$
Work Step by Step
$\sum_{i=1}^3({x_i}^2+x_i)$
$=({x_1}^2+x_1)+({x_2}^2+x_2)+({x_3}^2+x_3)$
$=((-2)^2+(-2))+((-1)^2+(-1))+(0^2+0)$
$=2+0+0$
$=\boxed{2}$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises - Page 1015: 64
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
