Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises: 79

Answer

$90$

Work Step by Step

$\sum ^{5}_{i=1}\left( 5i+3\right) =\sum ^{5}_{i=1}5i+\sum ^{5}_{i=1}3=5\times \dfrac {n\left( n+1\right) }{2}+3\times n=5\times \dfrac {5\times \left( 5+1\right) }{2}+3\times 5=90$
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