Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises - Page 1015: 80



Work Step by Step

$\sum ^{5}_{i=1}\left( 8i-1\right) =\sum ^{5}_{i=1}8i-\sum ^{5}_{i=1}1=8\times \dfrac {n\left( n+1\right) }{2}-1\times n=\dfrac {8\times 5\times \left( 5+1\right) }{2}-1\times 5=115$
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