Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.8 - Modeling with Equations - Exercise Set - Page 124: 33


$5$ inches

Work Step by Step

The original side is $ x $ inches (uknown). The sides are now $(x+3)$ inches each, and Area = $(x+3)^{2}$ $64=x^{2}+6x+9$ $0=x^{2}+6x-55$ Factor the RHS by finding factors of $-55$ with sum $+6$. We find $+11$ and $-5$ $0=(x+11)(x-5)$ $ w=-11$ is discarded as a negative side length, which makes no sense. $ w=5 $ (inches) is the original side length.
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