## Precalculus (6th Edition) Blitzer

The width of the path is $6$ feet.
With $x$ being the width of the path, the outer length equals $60+2x$ (two path widths added, one on either side), and the outer width equals $40+2x$ Perimeter $=2\times($ length + width) $=2(60+2x+40+2x)$ $=2(100+4x)$ $=200+8x$ Given that $200+8x=248,\qquad$ ... subtract $200$ $8x=48$ $x=6$ feet The width of the path is $6$ feet.