#### Answer

The width of the path is $6$ feet.

#### Work Step by Step

With $ x $ being the width of the path, the outer length equals $60+2x $ (two path widths added, one on either side), and the outer width equals $40+2x $
Perimeter $=2\times($ length + width)
$=2(60+2x+40+2x)$
$=2(100+4x)$
$=200+8x $
Given that $200+8x=248,\qquad $ ... subtract $200$
$8x=48$
$ x=6$ feet
The width of the path is $6$ feet.