Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.8 - Modeling with Equations - Exercise Set - Page 124: 32

Answer

The width of the parking lot is $12 $ yards, and the length is $15 $ yards.

Work Step by Step

With $ w $ being the width of the parking lot, its length is $ w+3$ Area = (width)$\times $(length) $180=w(w+3)$ $180=w^{2}+3w $ $0=w^{2}+3w-180$ Factor the RHS by finding factors of $-180$ with sum $+3$. We find $+15$ and $-12$ $0=(w+15)(w-12)$ $ w=-15$ is discarded as a negative width, which makes no sense. $ w=12$ (yards) is the width. The width of the parking lot is $12 $ yards, and the length is $15 $ yards.
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