Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.8 - Modeling with Equations - Exercise Set - Page 124: 31

Answer

The width of the sign is 6 feet, and the length is 9 feet.

Work Step by Step

With $ w $ being the width of the sign, its length is $ w+3$ Area = (width)$\times $(length) $54=w(w+3)$ $54=w^{2}+3w $ $0=w^{2}+3w-54$ Factor the RHS by finding factors of -54 with sum +3 We find $+9$ and $-6$ $0=(w+9)(w-6)$ $ w=-9$ is discarded as a negative width, which makes no sense. $ w=6$ (feet) is the width of the sign. The width of the sign is 6 feet, and the length is 9 feet.
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