## Precalculus (6th Edition) Blitzer

$(\dfrac{11}{19},\dfrac{7}{19})$
Re-arrange the given two equations to get $4x+10y=6$ ....(1) $15x-10y=5$ ...(2) After adding the above two equations, we get or, $19x =11$ This gives: $x=\dfrac{11}{19}$ Now, $3(\dfrac{11}{19})-2y=1 \implies y=\dfrac{7}{19}$ Our solution is: $(\dfrac{11}{19},\dfrac{7}{19})$