Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 7 - Mid-Chapter Check Point - Page 853: 5



Work Step by Step

Re-arrange the given two equations to get $4x+10y=6$ ....(1) $15x-10y=5$ ...(2) After adding the above two equations, we get or, $19x =11$ This gives: $x=\dfrac{11}{19}$ Now, $3(\dfrac{11}{19})-2y=1 \implies y=\dfrac{7}{19}$ Our solution is: $(\dfrac{11}{19},\dfrac{7}{19})$
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