## Precalculus (6th Edition) Blitzer

$(1,-2)$
$3x+4y=-5 \implies 9x+12y=-15$ ....(1) $2x-3y=8 \implies 8x-12y=32$ ....(1) After adding the above two equations, we get or, $17x =17$ This gives: $x=1$ Now, $3(1)+4y=-5 \implies y=-2$ Our solution is: $(1,-2)$