Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 7 - Mid-Chapter Check Point - Page 853: 2



Work Step by Step

$3x+4y=-5 \implies 9x+12y=-15$ ....(1) $2x-3y=8 \implies 8x-12y=32$ ....(1) After adding the above two equations, we get or, $17x =17$ This gives: $x=1$ Now, $3(1)+4y=-5 \implies y=-2$ Our solution is: $(1,-2)$
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