Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 7 - Mid-Chapter Check Point - Page 853: 3



Work Step by Step

Re-arrange the given two equations; we get $\dfrac{10x}{3}+y=30$ ....(1) $\dfrac{x}{3}+y=-8$ ...(2) After adding the above two equations, we get or, $11x =66$ This gives: $x=6$ Now, $\dfrac{10(6)}{3}+y=30 \implies y=10$ Our solution is: $(6,10)$
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