Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 7 - Mid-Chapter Check Point - Page 853: 12


$(0,-2)$, $(6,1)$

Work Step by Step

Re-arrange the given equations to get $x=2y+4$ $2y^2+(2y+4)y=8$ $ \implies y^2+y-2=0$ This gives: $ (y+2)(y-1)=0$ when $ y=-2$ gives: $x=-4+4=0$ when $ y=1$ gives: $x=2(1)+4=6$ Hence, our answers are: $(0,-2)$, $(6,1)$
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